0=t^2+2t+15

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Solution for 0=t^2+2t+15 equation: 



0=t^2+2t+15

We move all terms to the left:

0-(t^2+2t+15)=0

We add all the numbers together, and all the variables

-(t^2+2t+15)=0

We get rid of parentheses

-t^2-2t-15=0

We add all the numbers together, and all the variables

-1t^2-2t-15=0

a = -1; b = -2; c = -15;
Δ = b2-4ac
Δ = -22-4·(-1)·(-15)
Δ = -56
Delta is less than zero, so there is no solution for the equation

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